125331131543440 has 20 divisors (see below), whose sum is σ = 291394880838684. Its totient is φ = 50132452617344.

The previous prime is 125331131543419. The next prime is 125331131543441. The reversal of 125331131543440 is 44345131133521.

It can be written as a sum of positive squares in 2 ways, for example, as 62950958378896 + 62380173164544 = 7934164^2 + 7898112^2 .

It is a tau number, because it is divible by the number of its divisors (20).

It is a Harshad number since it is a multiple of its sum of digits (40).

It is a junction number, because it is equal to n+sod(n) for n = 125331131543393 and 125331131543402.

It is not an unprimeable number, because it can be changed into a prime (125331131543441) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 783319572067 + ... + 783319572226.

Almost surely, 2^{125331131543440} is an apocalyptic number.

125331131543440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

125331131543440 is an abundant number, since it is smaller than the sum of its proper divisors (166063749295244).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

125331131543440 is a wasteful number, since it uses less digits than its factorization.

125331131543440 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1566639144306 (or 1566639144300 counting only the distinct ones).

The product of its (nonzero) digits is 259200, while the sum is 40.

Adding to 125331131543440 its reverse (44345131133521), we get a palindrome (169676262676961).

The spelling of 125331131543440 in words is "one hundred twenty-five trillion, three hundred thirty-one billion, one hundred thirty-one million, five hundred forty-three thousand, four hundred forty".