Search a number
-
+
125341401151 = 2323922801783
BaseRepresentation
bin111010010111011101…
…1100000000000111111
3102222112020221220101201
41310232323200000333
54023144344314101
6133325301120331
712025035221341
oct1645673400077
9388466856351
10125341401151
114917aa5393a
12203606b90a7
13ba869ab275
1460d08b7291
1533d8d97e01
hex1d2eee003f

125341401151 has 8 divisors (see below), whose sum is σ = 131338275840. Its totient is φ = 119390130552.

The previous prime is 125341401083. The next prime is 125341401167. The reversal of 125341401151 is 151104143521.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-125341401151 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (125341401551) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 11395395 + ... + 11406388.

It is an arithmetic number, because the mean of its divisors is an integer number (16417284480).

Almost surely, 2125341401151 is an apocalyptic number.

125341401151 is a deficient number, since it is larger than the sum of its proper divisors (5996874689).

125341401151 is a wasteful number, since it uses less digits than its factorization.

125341401151 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 22802045.

The product of its (nonzero) digits is 2400, while the sum is 28.

Adding to 125341401151 its reverse (151104143521), we get a palindrome (276445544672).

The spelling of 125341401151 in words is "one hundred twenty-five billion, three hundred forty-one million, four hundred one thousand, one hundred fifty-one".

Divisors: 1 23 239 5497 22801783 524441009 5449626137 125341401151