Search a number
-
+
125421535000 = 235429098623
BaseRepresentation
bin111010011001110110…
…1001011111100011000
3102222201211202010101001
41310303231023330120
54023330403110000
6133341242434344
712030030312616
oct1646355137430
9388654663331
10125421535000
1149211206663
12203835029b4
13ba9a487548
1460db3b66b6
1533e0e2646a
hex1d33b4bf18

125421535000 has 80 divisors (see below), whose sum is σ = 293997765600. Its totient is φ = 50145552000.

The previous prime is 125421534947. The next prime is 125421535027. The reversal of 125421535000 is 535124521.

125421535000 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a super-2 number, since 2×1254215350002 (a number of 23 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 125421535000.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 14540689 + ... + 14549311.

It is an arithmetic number, because the mean of its divisors is an integer number (3674972070).

Almost surely, 2125421535000 is an apocalyptic number.

125421535000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 125421535000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (146998882800).

125421535000 is an abundant number, since it is smaller than the sum of its proper divisors (168576230600).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

125421535000 is an equidigital number, since it uses as much as digits as its factorization.

125421535000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11558 (or 11539 counting only the distinct ones).

The product of its (nonzero) digits is 6000, while the sum is 28.

Adding to 125421535000 its reverse (535124521), we get a palindrome (125956659521).

The spelling of 125421535000 in words is "one hundred twenty-five billion, four hundred twenty-one million, five hundred thirty-five thousand".

Divisors: 1 2 4 5 8 10 20 25 40 50 100 125 200 250 500 625 1000 1250 2500 2909 5000 5818 8623 11636 14545 17246 23272 29090 34492 43115 58180 68984 72725 86230 116360 145450 172460 215575 290900 344920 363625 431150 581800 727250 862300 1077875 1454500 1724600 1818125 2155750 2909000 3636250 4311500 5389375 7272500 8623000 10778750 14545000 21557500 25084307 43115000 50168614 100337228 125421535 200674456 250843070 501686140 627107675 1003372280 1254215350 2508430700 3135538375 5016861400 6271076750 12542153500 15677691875 25084307000 31355383750 62710767500 125421535000