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12543310132 = 223135827533
BaseRepresentation
bin10111010111010001…
…11011100100110100
31012101011110011201221
423223220323210310
5201142041411012
65432354400124
7622556243203
oct135350734464
935334404657
1012543310132
11535740a611
122520890044
13124b8a2002
1486dc4923a
154d62e1507
hex2eba3b934

12543310132 has 6 divisors (see below), whose sum is σ = 21950792738. Its totient is φ = 6271655064.

The previous prime is 12543310111. The next prime is 12543310139. The reversal of 12543310132 is 23101334521.

It is a happy number.

It can be written as a sum of positive squares in only one way, i.e., 12543104016 + 206116 = 111996^2 + 454^2 .

It is a junction number, because it is equal to n+sod(n) for n = 12543310097 and 12543310106.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12543310139) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1567913763 + ... + 1567913770.

Almost surely, 212543310132 is an apocalyptic number.

It is an amenable number.

12543310132 is a deficient number, since it is larger than the sum of its proper divisors (9407482606).

12543310132 is a wasteful number, since it uses less digits than its factorization.

12543310132 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3135827537 (or 3135827535 counting only the distinct ones).

The product of its (nonzero) digits is 2160, while the sum is 25.

Adding to 12543310132 its reverse (23101334521), we get a palindrome (35644644653).

The spelling of 12543310132 in words is "twelve billion, five hundred forty-three million, three hundred ten thousand, one hundred thirty-two".

Divisors: 1 2 4 3135827533 6271655066 12543310132