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12550113733 is a prime number
BaseRepresentation
bin10111011000000101…
…11000100111000101
31012101122020211112011
423230002320213011
5201200312114413
65433200254221
7623001130603
oct135402704705
935348224464
1012550113733
115360237223
122523011371
131250114a01
14870ada873
154d6bd733d
hex2ec0b89c5

12550113733 has 2 divisors, whose sum is σ = 12550113734. Its totient is φ = 12550113732.

The previous prime is 12550113727. The next prime is 12550113739. The reversal of 12550113733 is 33731105521.

It is a happy number.

It is a balanced prime because it is at equal distance from previous prime (12550113727) and next prime (12550113739).

It can be written as a sum of positive squares in only one way, i.e., 12500805249 + 49308484 = 111807^2 + 7022^2 .

It is an emirp because it is prime and its reverse (33731105521) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12550113733 - 213 = 12550105541 is a prime.

It is a super-2 number, since 2×125501137332 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 12550113695 and 12550113704.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12550113739) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6275056866 + 6275056867.

It is an arithmetic number, because the mean of its divisors is an integer number (6275056867).

Almost surely, 212550113733 is an apocalyptic number.

It is an amenable number.

12550113733 is a deficient number, since it is larger than the sum of its proper divisors (1).

12550113733 is an equidigital number, since it uses as much as digits as its factorization.

12550113733 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 9450, while the sum is 31.

The spelling of 12550113733 in words is "twelve billion, five hundred fifty million, one hundred thirteen thousand, seven hundred thirty-three".