Base | Representation |
---|---|
bin | 10111011000100000… |
… | …01110101100010111 |
3 | 1012101212211120022122 |
4 | 23230100032230113 |
5 | 201202211041210 |
6 | 5433403250155 |
7 | 623042641025 |
oct | 135420165427 |
9 | 35355746278 |
10 | 12553612055 |
11 | 53622065a6 |
12 | 252421995b |
13 | 1250a6b11a |
14 | 87136b715 |
15 | 4d7178b55 |
hex | 2ec40eb17 |
12553612055 has 4 divisors (see below), whose sum is σ = 15064334472. Its totient is φ = 10042889640.
The previous prime is 12553612031. The next prime is 12553612109. The reversal of 12553612055 is 55021635521.
12553612055 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 12553612055 - 216 = 12553546519 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1255361201 + ... + 1255361210.
It is an arithmetic number, because the mean of its divisors is an integer number (3766083618).
Almost surely, 212553612055 is an apocalyptic number.
12553612055 is a deficient number, since it is larger than the sum of its proper divisors (2510722417).
12553612055 is an equidigital number, since it uses as much as digits as its factorization.
12553612055 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2510722416.
The product of its (nonzero) digits is 45000, while the sum is 35.
The spelling of 12553612055 in words is "twelve billion, five hundred fifty-three million, six hundred twelve thousand, fifty-five".
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