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125542433 = 1771910271
BaseRepresentation
bin1110111101110…
…10000000100001
322202020012211202
413132322000201
5224114324213
620242450545
73053043632
oct736720041
9282205752
10125542433
1164957985
1236063a55
1320017883
141295d889
15b04cb58
hex77ba021

125542433 has 8 divisors (see below), whose sum is σ = 133125120. Its totient is φ = 117981760.

The previous prime is 125542427. The next prime is 125542463. The reversal of 125542433 is 334245521.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 125542433 - 212 = 125538337 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 125542396 and 125542405.

It is not an unprimeable number, because it can be changed into a prime (125542423) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 7088 + ... + 17358.

It is an arithmetic number, because the mean of its divisors is an integer number (16640640).

Almost surely, 2125542433 is an apocalyptic number.

It is an amenable number.

125542433 is a deficient number, since it is larger than the sum of its proper divisors (7582687).

125542433 is a wasteful number, since it uses less digits than its factorization.

125542433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11007.

The product of its digits is 14400, while the sum is 29.

The square root of 125542433 is about 11204.5719686207. The cubic root of 125542433 is about 500.7222003511.

Adding to 125542433 its reverse (334245521), we get a palindrome (459787954).

The spelling of 125542433 in words is "one hundred twenty-five million, five hundred forty-two thousand, four hundred thirty-three".

Divisors: 1 17 719 10271 12223 174607 7384849 125542433