Base | Representation |
---|---|
bin | 1011011010110011000010… |
… | …0111101011010010111111 |
3 | 1122110020122220010002200012 |
4 | 2312230300213223102333 |
5 | 3121200122302113120 |
6 | 42411404551453435 |
7 | 2434032505440353 |
oct | 266546047532277 |
9 | 48406586102605 |
10 | 12555005113535 |
11 | 4000603095215 |
12 | 14a92b198727b |
13 | 700c16509601 |
14 | 315946165463 |
15 | 16b8b7a101c5 |
hex | b6b309eb4bf |
12555005113535 has 16 divisors (see below), whose sum is σ = 15726687088320. Its totient is φ = 9603863301120.
The previous prime is 12555005113529. The next prime is 12555005113583. The reversal of 12555005113535 is 53531150055521.
It is not a de Polignac number, because 12555005113535 - 210 = 12555005112511 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12555005113492 and 12555005113501.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 19251506 + ... + 19892975.
It is an arithmetic number, because the mean of its divisors is an integer number (982917943020).
Almost surely, 212555005113535 is an apocalyptic number.
12555005113535 is a deficient number, since it is larger than the sum of its proper divisors (3171681974785).
12555005113535 is a wasteful number, since it uses less digits than its factorization.
12555005113535 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 39147298.
The product of its (nonzero) digits is 281250, while the sum is 41.
The spelling of 12555005113535 in words is "twelve trillion, five hundred fifty-five billion, five million, one hundred thirteen thousand, five hundred thirty-five".
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