Base | Representation |
---|---|
bin | 111010101011011101… |
… | …0011001101011100111 |
3 | 110001021000012002202121 |
4 | 1311112322121223213 |
5 | 4031033110423303 |
6 | 133520022450411 |
7 | 12050462020153 |
oct | 1652672315347 |
9 | 401230162677 |
10 | 126012201703 |
11 | 4949466a263 |
12 | 20509293a07 |
13 | bb62965b7b |
14 | 6155a10063 |
15 | 3427bed9bd |
hex | 1d56e99ae7 |
126012201703 has 2 divisors, whose sum is σ = 126012201704. Its totient is φ = 126012201702.
The previous prime is 126012201673. The next prime is 126012201709. The reversal of 126012201703 is 307102210621.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 126012201703 - 229 = 125475330791 is a prime.
It is a super-2 number, since 2×1260122017032 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (126012201709) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 63006100851 + 63006100852.
It is an arithmetic number, because the mean of its divisors is an integer number (63006100852).
Almost surely, 2126012201703 is an apocalyptic number.
126012201703 is a deficient number, since it is larger than the sum of its proper divisors (1).
126012201703 is an equidigital number, since it uses as much as digits as its factorization.
126012201703 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1008, while the sum is 25.
The spelling of 126012201703 in words is "one hundred twenty-six billion, twelve million, two hundred one thousand, seven hundred three".
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