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1263138263087 is a prime number
BaseRepresentation
bin10010011000011000111…
…010000101000000101111
311110202101021111012100212
4102120120322011000233
5131143401343404322
62404135552413035
7160154513040551
oct22303072050057
94422337435325
101263138263087
1144776a68a708
1218497a54717b
1392162278cac
14451c9ad54d1
1522cccbe40e2
hex12618e8502f

1263138263087 has 2 divisors, whose sum is σ = 1263138263088. Its totient is φ = 1263138263086.

The previous prime is 1263138263083. The next prime is 1263138263089. The reversal of 1263138263087 is 7803628313621.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1263138263087 - 22 = 1263138263083 is a prime.

Together with 1263138263089, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1263138263083) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 631569131543 + 631569131544.

It is an arithmetic number, because the mean of its divisors is an integer number (631569131544).

Almost surely, 21263138263087 is an apocalyptic number.

1263138263087 is a deficient number, since it is larger than the sum of its proper divisors (1).

1263138263087 is an equidigital number, since it uses as much as digits as its factorization.

1263138263087 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1741824, while the sum is 50.

The spelling of 1263138263087 in words is "one trillion, two hundred sixty-three billion, one hundred thirty-eight million, two hundred sixty-three thousand, eighty-seven".