Base | Representation |
---|---|
bin | 10111110101001010… |
… | …01111010100111111 |
3 | 1020000122011120112220 |
4 | 23322211033110333 |
5 | 202200231010303 |
6 | 5513311500423 |
7 | 632022132411 |
oct | 137245172477 |
9 | 36018146486 |
10 | 12794000703 |
11 | 5475975100 |
12 | 2590827713 |
13 | 128b7c6b23 |
14 | 8952649b1 |
15 | 4ed310053 |
hex | 2fa94f53f |
12794000703 has 48 divisors (see below), whose sum is σ = 19068650496. Its totient is φ = 7623000000.
The previous prime is 12794000699. The next prime is 12794000717. The reversal of 12794000703 is 30700049721.
12794000703 is a nontrivial binomial coefficient, being equal to C(159963, 2).
It is not a de Polignac number, because 12794000703 - 22 = 12794000699 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (33).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12794000203) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 17035578 + ... + 17036328.
It is an arithmetic number, because the mean of its divisors is an integer number (397263552).
Almost surely, 212794000703 is an apocalyptic number.
12794000703 is the 159962-nd triangular number.
12794000703 is a deficient number, since it is larger than the sum of its proper divisors (6274649793).
12794000703 is a wasteful number, since it uses less digits than its factorization.
12794000703 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1508 (or 1497 counting only the distinct ones).
The product of its (nonzero) digits is 10584, while the sum is 33.
The spelling of 12794000703 in words is "twelve billion, seven hundred ninety-four million, seven hundred three", and thus it is an aban number.
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