Base | Representation |
---|---|
bin | 10111111010001111… |
… | …10010110101111011 |
3 | 1020010121100112022121 |
4 | 23331013302311323 |
5 | 202242133112444 |
6 | 5521433102111 |
7 | 633050262103 |
oct | 137507626573 |
9 | 36117315277 |
10 | 12836613499 |
11 | 5497a2a796 |
12 | 25a2b57937 |
13 | 12975969b8 |
14 | 89ab98203 |
15 | 501e2b084 |
hex | 2fd1f2d7b |
12836613499 has 2 divisors, whose sum is σ = 12836613500. Its totient is φ = 12836613498.
The previous prime is 12836613497. The next prime is 12836613511. The reversal of 12836613499 is 99431663821.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12836613499 - 21 = 12836613497 is a prime.
It is a super-2 number, since 2×128366134992 (a number of 21 digits) contains 22 as substring.
Together with 12836613497, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (12836613497) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6418306749 + 6418306750.
It is an arithmetic number, because the mean of its divisors is an integer number (6418306750).
Almost surely, 212836613499 is an apocalyptic number.
12836613499 is a deficient number, since it is larger than the sum of its proper divisors (1).
12836613499 is an equidigital number, since it uses as much as digits as its factorization.
12836613499 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1679616, while the sum is 52.
The spelling of 12836613499 in words is "twelve billion, eight hundred thirty-six million, six hundred thirteen thousand, four hundred ninety-nine".
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