Search a number
-
+
1294399906800 = 24352711138312983
BaseRepresentation
bin10010110101100000001…
…111110010001111110000
311120202001221210020112220
4102311200033302033300
5132201412334004200
62430350014121040
7162342302446140
oct22654017621760
94522057706486
101294399906800
11459a520032a0
1218aa43ab0180
13950a4b39720
1446913918920
1523a0c4834a0
hex12d603f23f0

1294399906800 has 960 divisors, whose sum is σ = 5634695356416. Its totient is φ = 245266329600.

The previous prime is 1294399906781. The next prime is 1294399906817. The reversal of 1294399906800 is 86099934921.

It is a super-2 number, since 2×12943999068002 (a number of 25 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (60).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 191 ways as a sum of consecutive naturals, for example, 99693109 + ... + 99706091.

Almost surely, 21294399906800 is an apocalyptic number.

1294399906800 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1294399906800, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2817347678208).

1294399906800 is an abundant number, since it is smaller than the sum of its proper divisors (4340295449616).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1294399906800 is a wasteful number, since it uses less digits than its factorization.

1294399906800 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13118 (or 13107 counting only the distinct ones).

The product of its (nonzero) digits is 7558272, while the sum is 60.

The spelling of 1294399906800 in words is "one trillion, two hundred ninety-four billion, three hundred ninety-nine million, nine hundred six thousand, eight hundred".