Base | Representation |
---|---|
bin | 111100011000011000… |
… | …1100010001000100011 |
3 | 110101200201220211220020 |
4 | 1320300301202020203 |
5 | 4111024312410430 |
6 | 135322432244523 |
7 | 12240163644000 |
oct | 1706061421043 |
9 | 411621824806 |
10 | 129667310115 |
11 | 4aa9a8a8312 |
12 | 211693a0743 |
13 | c2c5c9c605 |
14 | 63c12268a7 |
15 | 358da48b10 |
hex | 1e30c62223 |
129667310115 has 64 divisors (see below), whose sum is σ = 248484249600. Its totient is φ = 57674332800.
The previous prime is 129667310107. The next prime is 129667310117. The reversal of 129667310115 is 511013766921.
It is not a de Polignac number, because 129667310115 - 23 = 129667310107 is a prime.
It is a super-2 number, since 2×1296673101152 (a number of 23 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (129667310117) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 150211 + ... + 530940.
It is an arithmetic number, because the mean of its divisors is an integer number (3882566400).
Almost surely, 2129667310115 is an apocalyptic number.
129667310115 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
129667310115 is a deficient number, since it is larger than the sum of its proper divisors (118816939485).
129667310115 is an equidigital number, since it uses as much as digits as its factorization.
129667310115 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 681217 (or 681203 counting only the distinct ones).
The product of its (nonzero) digits is 68040, while the sum is 42.
The spelling of 129667310115 in words is "one hundred twenty-nine billion, six hundred sixty-seven million, three hundred ten thousand, one hundred fifteen".
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