Base | Representation |
---|---|
bin | 111100100000111001… |
… | …1111011100000011000 |
3 | 110102102122210001212200 |
4 | 1321001303323200120 |
5 | 4112121001313000 |
6 | 135411043010200 |
7 | 12250234362231 |
oct | 1710163734030 |
9 | 412378701780 |
10 | 129953151000 |
11 | 50127190852 |
12 | 21229069960 |
13 | c34028072a |
14 | 640b192088 |
15 | 35a8bac500 |
hex | 1e41cfb818 |
129953151000 has 384 divisors, whose sum is σ = 485313379200. Its totient is φ = 31196774400.
The previous prime is 129953150989. The next prime is 129953151037. The reversal of 129953151000 is 151359921.
129953151000 is a `hidden beast` number, since 1 + 2 + 99 + 53 + 1 + 510 + 0 + 0 = 666.
129953151000 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a Harshad number since it is a multiple of its sum of digits (36).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 3500536 + ... + 3537464.
It is an arithmetic number, because the mean of its divisors is an integer number (1263836925).
Almost surely, 2129953151000 is an apocalyptic number.
129953151000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 129953151000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (242656689600).
129953151000 is an abundant number, since it is smaller than the sum of its proper divisors (355360228200).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
129953151000 is a wasteful number, since it uses less digits than its factorization.
129953151000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 36996 (or 36979 counting only the distinct ones).
The product of its (nonzero) digits is 12150, while the sum is 36.
It can be divided in two parts, 1299531 and 51000, that added together give a palindrome (1350531).
The spelling of 129953151000 in words is "one hundred twenty-nine billion, nine hundred fifty-three million, one hundred fifty-one thousand".
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