13000000000031 has 4 divisors (see below), whose sum is σ = 14181818181864. Its totient is φ = 11818181818200.

The previous prime is 13000000000027. The next prime is 13000000000033.

13000000000031 is nontrivially palindromic in base 10.

13000000000031 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13000000000031 - 2² = 13000000000027 is a prime.

It is a super-2 number, since 2×13000000000031² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12999999999928 and 13000000000018.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13000000000033) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 590909090900 + ... + 590909090921.

It is an arithmetic number, because the mean of its divisors is an integer number (3545454545466).

Almost surely, 2^{13000000000031} is an apocalyptic number.

13000000000031 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

13000000000031 is a deficient number, since it is larger than the sum of its proper divisors (1181818181833).

13000000000031 is a wasteful number, since it uses less digits than its factorization.

13000000000031 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1181818181832.

The product of its (nonzero) digits is 9, while the sum is 8.

It can be divided in two parts, 130000000000 and 31, that added together give a palindrome (130000000031).

The spelling of 13000000000031 in words is "thirteen trillion, thirty-one", and thus it is an aban number and an uban number.