Search a number
-
+
1300000112000 = 2753235366653
BaseRepresentation
bin10010111010101110000…
…010110111110110000000
311121021112020120010212022
4102322232002313312000
5132244400012041000
62433113430021012
7162631133426042
oct22725602676600
94537466503768
101300000112000
11461366199357
1218bb474a7768
1395788136405
1446cc55b7a92
1523c38e48585
hex12eae0b7d80

1300000112000 has 256 divisors, whose sum is σ = 3436338971520. Its totient is φ = 487999283200.

The previous prime is 1300000111979. The next prime is 1300000112003. The reversal of 1300000112000 is 2110000031.

It is a Harshad number since it is a multiple of its sum of digits (8).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1300000112003) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 19470674 + ... + 19537326.

Almost surely, 21300000112000 is an apocalyptic number.

1300000112000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1300000112000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1718169485760).

1300000112000 is an abundant number, since it is smaller than the sum of its proper divisors (2136338859520).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1300000112000 is an equidigital number, since it uses as much as digits as its factorization.

1300000112000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 66758 (or 66736 counting only the distinct ones).

The product of its (nonzero) digits is 6, while the sum is 8.

Adding to 1300000112000 its reverse (2110000031), we get a palindrome (1302110112031).

The spelling of 1300000112000 in words is "one trillion, three hundred billion, one hundred twelve thousand".