Search a number
-
+
13000012050000 = 24355550315749
BaseRepresentation
bin1011110100101100110100…
…0110011010111001010000
31201000210022012011201202210
42331023031012122321100
53200443011041100000
643352042330512120
72511135263126523
oct275131506327120
951023265151683
1013000012050000
114162301990078
12155b5a5895640
13733b853170b1
1432d2bd880bba
15178260767350
hexbd2cd19ae50

13000012050000 has 240 divisors, whose sum is σ = 41986812672000. Its totient is φ = 3465819840000.

The previous prime is 13000012049929. The next prime is 13000012050001. The reversal of 13000012050000 is 5021000031.

13000012050000 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a tau number, because it is divible by the number of its divisors (240).

It is a Harshad number since it is a multiple of its sum of digits (12).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13000012050001) by changing a digit.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 825442126 + ... + 825457874.

It is an arithmetic number, because the mean of its divisors is an integer number (174945052800).

Almost surely, 213000012050000 is an apocalyptic number.

13000012050000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13000012050000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (20993406336000).

13000012050000 is an abundant number, since it is smaller than the sum of its proper divisors (28986800622000).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13000012050000 is an equidigital number, since it uses as much as digits as its factorization.

13000012050000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 21288 (or 21262 counting only the distinct ones).

The product of its (nonzero) digits is 30, while the sum is 12.

Adding to 13000012050000 its reverse (5021000031), we get a palindrome (13005033050031).

The spelling of 13000012050000 in words is "thirteen trillion, twelve million, fifty thousand".