Base | Representation |
---|---|
bin | 10010111010101110001… |
… | …111001010000000000100 |
3 | 11121021112110121202000021 |
4 | 102322232033022000010 |
5 | 132244401323111400 |
6 | 2433114023024524 |
7 | 162631203000064 |
oct | 22725617120004 |
9 | 4537473552007 |
10 | 1300003332100 |
11 | 461367a986a0 |
12 | 18bb4859b144 |
13 | 957889c2cb5 |
14 | 46cc5bb53a4 |
15 | 23c3938271a |
hex | 12eae3ca004 |
1300003332100 has 144 divisors (see below), whose sum is σ = 3086227843776. Its totient is φ = 471384576000.
The previous prime is 1300003332077. The next prime is 1300003332107. The reversal of 1300003332100 is 12333000031.
It is a super-2 number, since 2×13000033321002 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (1300003332107) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 1110164515 + ... + 1110165685.
It is an arithmetic number, because the mean of its divisors is an integer number (21432137804).
Almost surely, 21300003332100 is an apocalyptic number.
1300003332100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 1300003332100, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1543113921888).
1300003332100 is an abundant number, since it is smaller than the sum of its proper divisors (1786224511676).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1300003332100 is a wasteful number, since it uses less digits than its factorization.
1300003332100 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3206 (or 3199 counting only the distinct ones).
The product of its (nonzero) digits is 162, while the sum is 16.
Adding to 1300003332100 its reverse (12333000031), we get a palindrome (1312336332131).
The spelling of 1300003332100 in words is "one trillion, three hundred billion, three million, three hundred thirty-two thousand, one hundred".
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