130001010100111 has 4 divisors (see below), whose sum is σ = 137648128341312. Its totient is φ = 122353891858912.

The previous prime is 130001010100103. The next prime is 130001010100133. The reversal of 130001010100111 is 111001010100031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 130001010100111 - 2³ = 130001010100103 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130001010104111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3823559120575 + ... + 3823559120608.

It is an arithmetic number, because the mean of its divisors is an integer number (34412032085328).

Almost surely, 2^{130001010100111} is an apocalyptic number.

130001010100111 is a deficient number, since it is larger than the sum of its proper divisors (7647118241201).

130001010100111 is an equidigital number, since it uses as much as digits as its factorization.

130001010100111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7647118241200.

The product of its (nonzero) digits is 3, while the sum is 10.

Adding to 130001010100111 its reverse (111001010100031), we get a palindrome (241002020200142).

The spelling of 130001010100111 in words is "one hundred thirty trillion, one billion, ten million, one hundred thousand, one hundred eleven".