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13000101120000 = 21132546716843
BaseRepresentation
bin1011110100101101001001…
…1010001100100000000000
31201000210112101202221211200
42331023102122030200000
53200443201341320000
643352055231541200
72511140424200031
oct275132232144000
951023471687750
1013000101120000
114162348196745
12155b60b68a800
13733b9a901937
1432d2cb628a88
151782684ad500
hexbd2d268c800

13000101120000 has 720 divisors, whose sum is σ = 47621430576720. Its totient is φ = 3414749184000.

The previous prime is 13000101119977. The next prime is 13000101120011. The reversal of 13000101120000 is 2110100031.

It is a tau number, because it is divible by the number of its divisors (720).

It is a Harshad number since it is a multiple of its sum of digits (9).

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 59 ways as a sum of consecutive naturals, for example, 771831579 + ... + 771848421.

It is an arithmetic number, because the mean of its divisors is an integer number (66140875801).

Almost surely, 213000101120000 is an apocalyptic number.

13000101120000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13000101120000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (23810715288360).

13000101120000 is an abundant number, since it is smaller than the sum of its proper divisors (34621329456720).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13000101120000 is an equidigital number, since it uses as much as digits as its factorization.

13000101120000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 16958 (or 16920 counting only the distinct ones).

The product of its (nonzero) digits is 6, while the sum is 9.

Adding to 13000101120000 its reverse (2110100031), we get a palindrome (13002211220031).

The spelling of 13000101120000 in words is "thirteen trillion, one hundred one million, one hundred twenty thousand".