Base | Representation |
---|---|
bin | 11101100011110000111110… |
… | …101001101100100001101100 |
3 | 122001021222121122210211022010 |
4 | 131203300332221230201230 |
5 | 114014414244013424004 |
6 | 1140253405101521220 |
7 | 36245161655060400 |
oct | 3543607651544154 |
9 | 561258548724263 |
10 | 130001121233004 |
11 | 384711908a517a |
12 | 126b7108573210 |
13 | 577008c95b578 |
14 | 2416133067100 |
15 | 1006962c25a89 |
hex | 763c3ea6c86c |
130001121233004 has 144 divisors (see below), whose sum is σ = 378345994951680. Its totient is φ = 34515774558720.
The previous prime is 130001121232991. The next prime is 130001121233131. The reversal of 130001121233004 is 400332121100031.
It is a Harshad number since it is a multiple of its sum of digits (21).
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 81522432 + ... + 83101799.
It is an arithmetic number, because the mean of its divisors is an integer number (2627402742720).
Almost surely, 2130001121233004 is an apocalyptic number.
130001121233004 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
It is an amenable number.
130001121233004 is an abundant number, since it is smaller than the sum of its proper divisors (248344873718676).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130001121233004 is a wasteful number, since it uses less digits than its factorization.
130001121233004 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 164624348 (or 164624339 counting only the distinct ones).
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 130001121233004 its reverse (400332121100031), we get a palindrome (530333242333035).
The spelling of 130001121233004 in words is "one hundred thirty trillion, one billion, one hundred twenty-one million, two hundred thirty-three thousand, four".
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