130001211013 has 4 divisors (see below), whose sum is σ = 130950125100. Its totient is φ = 129052296928.

The previous prime is 130001211007. The next prime is 130001211017. The reversal of 130001211013 is 310112100031.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 310112100031 = 13523 ⋅22932197.

It can be written as a sum of positive squares in 2 ways, for example, as 96635804769 + 33365406244 = 310863^2 + 182662^2 .

It is a cyclic number.

It is not a de Polignac number, because 130001211013 - 2²¹ = 129999113861 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 130001210984 and 130001211002.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130001211017) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 474456838 + ... + 474457111.

It is an arithmetic number, because the mean of its divisors is an integer number (32737531275).

Almost surely, 2^130001211013 is an apocalyptic number.

It is an amenable number.

130001211013 is a deficient number, since it is larger than the sum of its proper divisors (948914087).

130001211013 is an equidigital number, since it uses as much as digits as its factorization.

130001211013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 948914086.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 130001211013 its reverse (310112100031), we get a palindrome (440113311044).

It can be divided in two parts, 1300012 and 11013, that added together give a square (1311025 = 1145²).

The spelling of 130001211013 in words is "one hundred thirty billion, one million, two hundred eleven thousand, thirteen".