1300012114901 has 2 divisors, whose sum is σ = 1300012114902. Its totient is φ = 1300012114900.

The previous prime is 1300012114853. The next prime is 1300012114903. The reversal of 1300012114901 is 1094112100031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1249365062500 + 50647052401 = 1117750^2 + 225049^2 .

It is a cyclic number.

It is not a de Polignac number, because 1300012114901 - 2²² = 1300007920597 is a prime.

Together with 1300012114903, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1300012114903) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650006057450 + 650006057451.

It is an arithmetic number, because the mean of its divisors is an integer number (650006057451).

Almost surely, 2^{1300012114901} is an apocalyptic number.

It is an amenable number.

1300012114901 is a deficient number, since it is larger than the sum of its proper divisors (1).

1300012114901 is an equidigital number, since it uses as much as digits as its factorization.

1300012114901 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 216, while the sum is 23.

Adding to 1300012114901 its reverse (1094112100031), we get a palindrome (2394124214932).

The spelling of 1300012114901 in words is "one trillion, three hundred billion, twelve million, one hundred fourteen thousand, nine hundred one".