Base | Representation |
---|---|
bin | 1011110100101101100100… |
… | …0001010000000000111111 |
3 | 1201000210211010110022211122 |
4 | 2331023121001100000333 |
5 | 3200443413234140221 |
6 | 43352114232541155 |
7 | 2511143241634334 |
oct | 275133101200077 |
9 | 51023733408748 |
10 | 13000212021311 |
11 | 41623a4853519 |
12 | 155b6408517bb |
13 | 733bb7891308 |
14 | 32d2dc25698b |
15 | 1782730b7eab |
hex | bd2d905003f |
13000212021311 has 2 divisors, whose sum is σ = 13000212021312. Its totient is φ = 13000212021310.
The previous prime is 13000212021259. The next prime is 13000212021323. The reversal of 13000212021311 is 11312021200031.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13000212021311 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13000212021311.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13000212021341) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6500106010655 + 6500106010656.
It is an arithmetic number, because the mean of its divisors is an integer number (6500106010656).
Almost surely, 213000212021311 is an apocalyptic number.
13000212021311 is a deficient number, since it is larger than the sum of its proper divisors (1).
13000212021311 is an equidigital number, since it uses as much as digits as its factorization.
13000212021311 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 13000212021311 its reverse (11312021200031), we get a palindrome (24312233221342).
The spelling of 13000212021311 in words is "thirteen trillion, two hundred twelve million, twenty-one thousand, three hundred eleven".
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