130002221311 has 4 divisors (see below), whose sum is σ = 130219254000. Its totient is φ = 129785188624.

The previous prime is 130002221299. The next prime is 130002221357. The reversal of 130002221311 is 113122200031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 130002221311 - 2¹⁵ = 130002188543 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130002221711) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 108515446 + ... + 108516643.

It is an arithmetic number, because the mean of its divisors is an integer number (32554813500).

Almost surely, 2^130002221311 is an apocalyptic number.

130002221311 is a deficient number, since it is larger than the sum of its proper divisors (217032689).

130002221311 is an equidigital number, since it uses as much as digits as its factorization.

130002221311 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 217032688.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 130002221311 its reverse (113122200031), we get a palindrome (243124421342).

The spelling of 130002221311 in words is "one hundred thirty billion, two million, two hundred twenty-one thousand, three hundred eleven".