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130002311132 = 2275353431311
BaseRepresentation
bin111100100010010111…
…1011101011111011100
3110102120002021122220022
41321010233131133130
54112221042424012
6135420000411312
712251402261231
oct1710457353734
9412502248808
10130002311132
1150151a08561
1221241616b38
13c34a503775
14641390b788
1535ad16d472
hex1e44bdd7dc

130002311132 has 12 divisors (see below), whose sum is σ = 227507591136. Its totient is φ = 65000142240.

The previous prime is 130002311113. The next prime is 130002311147. The reversal of 130002311132 is 231113200031.

It is a super-2 number, since 2×1300023111322 (a number of 23 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 130002311132.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 85757 + ... + 517067.

It is an arithmetic number, because the mean of its divisors is an integer number (18958965928).

Almost surely, 2130002311132 is an apocalyptic number.

It is an amenable number.

130002311132 is a deficient number, since it is larger than the sum of its proper divisors (97505280004).

130002311132 is a wasteful number, since it uses less digits than its factorization.

130002311132 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 506668 (or 506666 counting only the distinct ones).

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 130002311132 its reverse (231113200031), we get a palindrome (361115511163).

The spelling of 130002311132 in words is "one hundred thirty billion, two million, three hundred eleven thousand, one hundred thirty-two".

Divisors: 1 2 4 75353 150706 301412 431311 862622 1725244 32500577783 65001155566 130002311132