Base | Representation |
---|---|
bin | 10010111010101111011… |
… | …110111011001101100100 |
3 | 11121021120220222010102200 |
4 | 102322233132323031210 |
5 | 132244422201234134 |
6 | 2433120051134500 |
7 | 162631545511662 |
oct | 22725736731544 |
9 | 4537526863380 |
10 | 1300024243044 |
11 | 46137888036a |
12 | 18bb535a4430 |
13 | 95790134c37 |
14 | 46cc8899c32 |
15 | 23c3b113499 |
hex | 12eaf7bb364 |
1300024243044 has 72 divisors (see below), whose sum is σ = 3316999445760. Its totient is φ = 429289848000.
The previous prime is 1300024243043. The next prime is 1300024243069. The reversal of 1300024243044 is 4403424200031.
It is a happy number.
It is a junction number, because it is equal to n+sod(n) for n = 1300024242999 and 1300024243017.
It is not an unprimeable number, because it can be changed into a prime (1300024243043) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 2025069 + ... + 2588619.
Almost surely, 21300024243044 is an apocalyptic number.
It is an amenable number.
1300024243044 is an abundant number, since it is smaller than the sum of its proper divisors (2016975202716).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1300024243044 is a wasteful number, since it uses less digits than its factorization.
1300024243044 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 564161 (or 564156 counting only the distinct ones).
The product of its (nonzero) digits is 9216, while the sum is 27.
Adding to 1300024243044 its reverse (4403424200031), we get a palindrome (5703448443075).
The spelling of 1300024243044 in words is "one trillion, three hundred billion, twenty-four million, two hundred forty-three thousand, forty-four".
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