Base | Representation |
---|---|
bin | 11000001101110000… |
… | …10000010101000011 |
3 | 1020120000101021121220 |
4 | 30012320100111003 |
5 | 203111034442011 |
6 | 5550001450123 |
7 | 640105554432 |
oct | 140670202503 |
9 | 36500337556 |
10 | 13000312131 |
11 | 5571378a14 |
12 | 2629940943 |
13 | 12c2480ab1 |
14 | 8b480b119 |
15 | 5114b4506 |
hex | 306e10543 |
13000312131 has 48 divisors (see below), whose sum is σ = 18792496608. Its totient is φ = 7990272000.
The previous prime is 13000312099. The next prime is 13000312139. The reversal of 13000312131 is 13121300031.
It is not a de Polignac number, because 13000312131 - 25 = 13000312099 is a prime.
It is a super-2 number, since 2×130003121312 (a number of 21 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 13000312131.
It is not an unprimeable number, because it can be changed into a prime (13000312139) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 21207381 + ... + 21207993.
It is an arithmetic number, because the mean of its divisors is an integer number (391510346).
Almost surely, 213000312131 is an apocalyptic number.
13000312131 is a deficient number, since it is larger than the sum of its proper divisors (5792184477).
13000312131 is a wasteful number, since it uses less digits than its factorization.
13000312131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1112 (or 1095 counting only the distinct ones).
The product of its (nonzero) digits is 54, while the sum is 15.
Adding to 13000312131 its reverse (13121300031), we get a palindrome (26121612162).
The spelling of 13000312131 in words is "thirteen billion, three hundred twelve thousand, one hundred thirty-one".
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