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130003122021300 = 22325211234317974177
BaseRepresentation
bin11101100011110010110101…
…111010000110001110110100
3122001022011210002122101212100
4131203302311322012032310
5114014432343214140200
61140254335413422100
736245262361354413
oct3543626572061664
9561264702571770
10130003122021300
1138472018230020
12126b758663a930
13577031b320678
142416282a8947a
151006a2d6e1d00
hex763cb5e863b4

130003122021300 has 864 divisors, whose sum is σ = 477304880532480. Its totient is φ = 29279700172800.

The previous prime is 130003122021221. The next prime is 130003122021361. The reversal of 130003122021300 is 3120221300031.

130003122021300 is a `hidden beast` number, since 1 + 30 + 0 + 0 + 312 + 2 + 0 + 21 + 300 = 666.

130003122021300 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 287 ways as a sum of consecutive naturals, for example, 1752569812 + ... + 1752643988.

It is an arithmetic number, because the mean of its divisors is an integer number (552436204320).

Almost surely, 2130003122021300 is an apocalyptic number.

130003122021300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 130003122021300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (238652440266240).

130003122021300 is an abundant number, since it is smaller than the sum of its proper divisors (347301758511180).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130003122021300 is a wasteful number, since it uses less digits than its factorization.

130003122021300 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 74453 (or 74443 counting only the distinct ones).

The product of its (nonzero) digits is 216, while the sum is 18.

Adding to 130003122021300 its reverse (3120221300031), we get a palindrome (133123343321331).

The spelling of 130003122021300 in words is "one hundred thirty trillion, three billion, one hundred twenty-two million, twenty-one thousand, three hundred".