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13000350021120 = 2932571119253383
BaseRepresentation
bin1011110100101110000100…
…1111101011011000000000
31201000211011202010102222200
42331023201033223120000
53200444204101133440
643352140042433200
72511146535624210
oct275134117533000
951024152112880
1013000350021120
114162465739850
12155b67ab02800
13733c0a34b0c7
1432d3126da240
15178280276c30
hexbd2e13eb600

13000350021120 has 2880 divisors, whose sum is σ = 60518956253184. Its totient is φ = 2504351416320.

The previous prime is 13000350021107. The next prime is 13000350021137. The reversal of 13000350021120 is 2112005300031.

13000350021120 is a `hidden beast` number, since 1 + 300 + 0 + 350 + 0 + 2 + 1 + 12 + 0 = 666.

It is a tau number, because it is divible by the number of its divisors (2880).

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a junction number, because it is equal to n+sod(n) for n = 13000350021093 and 13000350021102.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 287 ways as a sum of consecutive naturals, for example, 33943472449 + ... + 33943472831.

Almost surely, 213000350021120 is an apocalyptic number.

13000350021120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13000350021120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (30259478126592).

13000350021120 is an abundant number, since it is smaller than the sum of its proper divisors (47518606232064).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13000350021120 is a wasteful number, since it uses less digits than its factorization.

13000350021120 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 521 (or 483 counting only the distinct ones).

The product of its (nonzero) digits is 180, while the sum is 18.

Adding to 13000350021120 its reverse (2112005300031), we get a palindrome (15112355321151).

The spelling of 13000350021120 in words is "thirteen trillion, three hundred fifty million, twenty-one thousand, one hundred twenty".