130004023 has 4 divisors (see below), whose sum is σ = 136846360. Its totient is φ = 123161688.

The previous prime is 130004011. The next prime is 130004029. The reversal of 130004023 is 320400031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 130004023 - 2²¹ = 127906871 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 130003994 and 130004012.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130004029) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3421140 + ... + 3421177.

It is an arithmetic number, because the mean of its divisors is an integer number (34211590).

Almost surely, 2^130004023 is an apocalyptic number.

130004023 is a deficient number, since it is larger than the sum of its proper divisors (6842337).

130004023 is an equidigital number, since it uses as much as digits as its factorization.

130004023 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6842336.

The product of its (nonzero) digits is 72, while the sum is 13.

The square root of 130004023 is about 11401.9306698471. The cubic root of 130004023 is about 506.5849274206.

Adding to 130004023 its reverse (320400031), we get a palindrome (450404054).

The spelling of 130004023 in words is "one hundred thirty million, four thousand, twenty-three".