130004261 has 2 divisors, whose sum is σ = 130004262. Its totient is φ = 130004260.

The previous prime is 130004243. The next prime is 130004263. The reversal of 130004261 is 162400031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 106481761 + 23522500 = 10319^2 + 4850^2 .

It is a cyclic number.

It is not a de Polignac number, because 130004261 - 2⁶ = 130004197 is a prime.

It is a super-2 number, since 2×130004261² = 33802215756312242, which contains 22 as substring.

Together with 130004263, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130004263) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65002130 + 65002131.

It is an arithmetic number, because the mean of its divisors is an integer number (65002131).

Almost surely, 2^130004261 is an apocalyptic number.

It is an amenable number.

130004261 is a deficient number, since it is larger than the sum of its proper divisors (1).

130004261 is an equidigital number, since it uses as much as digits as its factorization.

130004261 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 17.

The square root of 130004261 is about 11401.9411066713. The cubic root of 130004261 is about 506.5852365576.

Adding to 130004261 its reverse (162400031), we get a palindrome (292404292).

The spelling of 130004261 in words is "one hundred thirty million, four thousand, two hundred sixty-one".