1300045 has 4 divisors (see below), whose sum is σ = 1560060. Its totient is φ = 1040032.

The previous prime is 1300031. The next prime is 1300051. The reversal of 1300045 is 5400031.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 224676 + 1075369 = 474^2 + 1037^2 .

It is a cyclic number.

It is not a de Polignac number, because 1300045 - 2⁷ = 1299917 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1299998 and 1300034.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 130000 + ... + 130009.

It is an arithmetic number, because the mean of its divisors is an integer number (390015).

2^1300045 is an apocalyptic number.

It is an amenable number.

1300045 is a deficient number, since it is larger than the sum of its proper divisors (260015).

1300045 is an equidigital number, since it uses as much as digits as its factorization.

1300045 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 260014.

The product of its (nonzero) digits is 60, while the sum is 13.

The square root of 1300045 is about 1140.1951587338. The cubic root of 1300045 is about 109.1405475911.

Adding to 1300045 its reverse (5400031), we get a palindrome (6700076).

The spelling of 1300045 in words is "one million, three hundred thousand, forty-five".