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130010101141 is a prime number
BaseRepresentation
bin111100100010100110…
…1001011010110010101
3110102120121221102210011
41321011031023112111
54112230041214031
6135420435400221
712251525424514
oct1710515132625
9412517842704
10130010101141
1150156349288
1221244153071
13c34c00043b
14641497867b
1535adbab6b1
hex1e4534b595

130010101141 has 2 divisors, whose sum is σ = 130010101142. Its totient is φ = 130010101140.

The previous prime is 130010101079. The next prime is 130010101147. The reversal of 130010101141 is 141101010031.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 73416070116 + 56594031025 = 270954^2 + 237895^2 .

It is a cyclic number.

It is not a de Polignac number, because 130010101141 - 215 = 130010068373 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130010101147) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65005050570 + 65005050571.

It is an arithmetic number, because the mean of its divisors is an integer number (65005050571).

Almost surely, 2130010101141 is an apocalyptic number.

It is an amenable number.

130010101141 is a deficient number, since it is larger than the sum of its proper divisors (1).

130010101141 is an equidigital number, since it uses as much as digits as its factorization.

130010101141 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12, while the sum is 13.

Adding to 130010101141 its reverse (141101010031), we get a palindrome (271111111172).

The spelling of 130010101141 in words is "one hundred thirty billion, ten million, one hundred one thousand, one hundred forty-one".