Base | Representation |
---|---|
bin | 11101100011111010001101… |
… | …110111101010111001101110 |
3 | 122001022221012221011010121002 |
4 | 131203322031313222321232 |
5 | 114020100102244343042 |
6 | 1140302125232240302 |
7 | 36245662530134066 |
oct | 3543721567527156 |
9 | 561287187133532 |
10 | 130011040231022 |
11 | 384754109141a5 |
12 | 126b90163a0092 |
13 | 5770cb0927572 |
14 | 24167d45423a6 |
15 | 1006d43933132 |
hex | 763e8ddeae6e |
130011040231022 has 8 divisors (see below), whose sum is σ = 195022376108136. Its totient is φ = 65003581528312.
The previous prime is 130011040231021. The next prime is 130011040231049. The reversal of 130011040231022 is 220132040110031.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a junction number, because it is equal to n+sod(n) for n = 130011040230985 and 130011040231003.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130011040231021) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 969209768 + ... + 969343899.
It is an arithmetic number, because the mean of its divisors is an integer number (24377797013517).
Almost surely, 2130011040231022 is an apocalyptic number.
130011040231022 is a deficient number, since it is larger than the sum of its proper divisors (65011335877114).
130011040231022 is a wasteful number, since it uses less digits than its factorization.
130011040231022 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1938587202.
The product of its (nonzero) digits is 288, while the sum is 20.
Adding to 130011040231022 its reverse (220132040110031), we get a palindrome (350143080341053).
The spelling of 130011040231022 in words is "one hundred thirty trillion, eleven billion, forty million, two hundred thirty-one thousand, twenty-two".
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