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130011240330104 = 23723100940403983
BaseRepresentation
bin11101100011111010011001…
…110010111111001101111000
3122001022221201212200012221012
4131203322121302333031320
5114020101010011030404
61140302201141133052
736246000510013250
oct3543723162771570
9561287655605835
10130011240330104
1138475503864641
12126b90713ba188
1357710132179a3
142416812d4c960
151006d562aba6e
hex763e99cbf378

130011240330104 has 32 divisors (see below), whose sum is σ = 290708363473920. Its totient is φ = 53296533302496.

The previous prime is 130011240330079. The next prime is 130011240330107. The reversal of 130011240330104 is 401033042110031.

It is a super-2 number, since 2×1300112403301042 (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (23).

It is a self number, because there is not a number n which added to its sum of digits gives 130011240330104.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130011240330107) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 50470200704 + ... + 50470203279.

It is an arithmetic number, because the mean of its divisors is an integer number (9084636358560).

Almost surely, 2130011240330104 is an apocalyptic number.

130011240330104 is a gapful number since it is divisible by the number (14) formed by its first and last digit.

It is an amenable number.

130011240330104 is an abundant number, since it is smaller than the sum of its proper divisors (160697123143816).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130011240330104 is a wasteful number, since it uses less digits than its factorization.

130011240330104 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 100940404019 (or 100940404015 counting only the distinct ones).

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 130011240330104 its reverse (401033042110031), we get a palindrome (531044282440135).

The spelling of 130011240330104 in words is "one hundred thirty trillion, eleven billion, two hundred forty million, three hundred thirty thousand, one hundred four".

Divisors: 1 2 4 7 8 14 23 28 46 56 92 161 184 322 644 1288 100940403983 201880807966 403761615932 706582827881 807523231864 1413165655762 2321629291609 2826331311524 4643258583218 5652662623048 9286517166436 16251405041263 18573034332872 32502810082526 65005620165052 130011240330104