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13001134310 = 251300113431
BaseRepresentation
bin11000001101110110…
…11001000011100110
31020120001221001102222
430012323121003212
5203111242244220
65550031232342
7640115550443
oct140673310346
936501831388
1013001134310
11557188a6aa
12262a0786b2
1312c26ab0a8
148b49829ca
155115c7e25
hex306ed90e6

13001134310 has 8 divisors (see below), whose sum is σ = 23402041776. Its totient is φ = 5200453720.

The previous prime is 13001134309. The next prime is 13001134339. The reversal of 13001134310 is 1343110031.

13001134310 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×130011343102 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 650056706 + ... + 650056725.

It is an arithmetic number, because the mean of its divisors is an integer number (2925255222).

Almost surely, 213001134310 is an apocalyptic number.

13001134310 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

13001134310 is a deficient number, since it is larger than the sum of its proper divisors (10400907466).

13001134310 is a wasteful number, since it uses less digits than its factorization.

13001134310 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1300113438.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 13001134310 its reverse (1343110031), we get a palindrome (14344244341).

The spelling of 13001134310 in words is "thirteen billion, one million, one hundred thirty-four thousand, three hundred ten".

Divisors: 1 2 5 10 1300113431 2600226862 6500567155 13001134310