Search a number
-
+
130012110014207 is a prime number
BaseRepresentation
bin11101100011111011001101…
…101000100100011011111111
3122001100000222111010202020112
4131203323031220210123333
5114020104300130423312
61140302423325340235
736246031200136361
oct3543731550443377
9561300874122215
10130012110014207
113847590a770133
12126b927470767b
135771121458675
142416896656d31
151006da77ead22
hex763ecda246ff

130012110014207 has 2 divisors, whose sum is σ = 130012110014208. Its totient is φ = 130012110014206.

The previous prime is 130012110014057. The next prime is 130012110014239. The reversal of 130012110014207 is 702410011210031.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 130012110014207 - 210 = 130012110013183 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130012110514207) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65006055007103 + 65006055007104.

It is an arithmetic number, because the mean of its divisors is an integer number (65006055007104).

Almost surely, 2130012110014207 is an apocalyptic number.

130012110014207 is a deficient number, since it is larger than the sum of its proper divisors (1).

130012110014207 is an equidigital number, since it uses as much as digits as its factorization.

130012110014207 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 336, while the sum is 23.

Adding to 130012110014207 its reverse (702410011210031), we get a palindrome (832422121224238).

The spelling of 130012110014207 in words is "one hundred thirty trillion, twelve billion, one hundred ten million, fourteen thousand, two hundred seven".