Base | Representation |
---|---|
bin | 111100100010101010… |
… | …0111000100010001111 |
3 | 110102120202202001211022 |
4 | 1321011110320202033 |
5 | 4112231100334411 |
6 | 135420550544355 |
7 | 12251551540136 |
oct | 1710524704217 |
9 | 412522661738 |
10 | 130012121231 |
11 | 501574a8a83 |
12 | 212449680bb |
13 | c34c559a65 |
14 | 6414d4291d |
15 | 35ade59edb |
hex | 1e4553888f |
130012121231 has 4 divisors (see below), whose sum is σ = 130840224072. Its totient is φ = 129184018392.
The previous prime is 130012121221. The next prime is 130012121233. The reversal of 130012121231 is 132121210031.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 130012121231 - 210 = 130012120207 is a prime.
It is a super-2 number, since 2×1300121212312 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130012121233) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 414051185 + ... + 414051498.
It is an arithmetic number, because the mean of its divisors is an integer number (32710056018).
Almost surely, 2130012121231 is an apocalyptic number.
130012121231 is a deficient number, since it is larger than the sum of its proper divisors (828102841).
130012121231 is an equidigital number, since it uses as much as digits as its factorization.
130012121231 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 828102840.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 130012121231 its reverse (132121210031), we get a palindrome (262133331262).
The spelling of 130012121231 in words is "one hundred thirty billion, twelve million, one hundred twenty-one thousand, two hundred thirty-one".
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