Base | Representation |
---|---|
bin | 1011110100110001010100… |
… | …1110110100000111101111 |
3 | 1201000220102112022020020200 |
4 | 2331030111032310013233 |
5 | 3201003000341210111 |
6 | 43352402400444543 |
7 | 2511210256252056 |
oct | 275142516640757 |
9 | 51026375266220 |
10 | 13001222210031 |
11 | 4162872aa6230 |
12 | 155b883019753 |
13 | 734018c57c13 |
14 | 32d39649739d |
15 | 1782d1b0d256 |
hex | bd3153b41ef |
13001222210031 has 24 divisors (see below), whose sum is σ = 20487589784064. Its totient is φ = 7879214999760.
The previous prime is 13001222210023. The next prime is 13001222210063.
13001222210031 is a `hidden beast` number, since 1 + 300 + 12 + 222 + 100 + 31 = 666.
13001222210031 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 13001222210031 - 23 = 13001222210023 is a prime.
It is a super-2 number, since 2×130012222100312 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13001222209986 and 13001222210013.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13001222210131) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 101361 + ... + 5100266.
It is an arithmetic number, because the mean of its divisors is an integer number (853649574336).
Almost surely, 213001222210031 is an apocalyptic number.
13001222210031 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
13001222210031 is a deficient number, since it is larger than the sum of its proper divisors (7486367574033).
13001222210031 is a wasteful number, since it uses less digits than its factorization.
13001222210031 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5226891 (or 5226888 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 18.
It can be divided in two parts, 1300122 and 2210031, that added together give a palindrome (3510153).
The spelling of 13001222210031 in words is "thirteen trillion, one billion, two hundred twenty-two million, two hundred ten thousand, thirty-one".
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