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13001223302100 = 2232521117292663803
BaseRepresentation
bin1011110100110001010101…
…0010111110101111010100
31201000220102121100201021200
42331030111102332233110
53201003001131131400
643352402440112500
72511210301450665
oct275142522765724
951026377321250
1013001223302100
114162873681770
12155b883465730
1373401924b007
1432d39669d36c
151782d1c76b00
hexbd3154bebd4

13001223302100 has 432 divisors, whose sum is σ = 48694550224320. Its totient is φ = 2864119910400.

The previous prime is 13001223302059. The next prime is 13001223302107. The reversal of 13001223302100 is 120332210031.

13001223302100 is a `hidden beast` number, since 1 + 3 + 0 + 0 + 122 + 330 + 210 + 0 = 666.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13001223302107) by changing a digit.

It is a polite number, since it can be written in 143 ways as a sum of consecutive naturals, for example, 3548799 + ... + 6212601.

It is an arithmetic number, because the mean of its divisors is an integer number (112718866260).

Almost surely, 213001223302100 is an apocalyptic number.

13001223302100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13001223302100, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (24347275112160).

13001223302100 is an abundant number, since it is smaller than the sum of its proper divisors (35693326922220).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13001223302100 is a wasteful number, since it uses less digits than its factorization.

13001223302100 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2663880 (or 2663870 counting only the distinct ones).

The product of its (nonzero) digits is 216, while the sum is 18.

Adding to 13001223302100 its reverse (120332210031), we get a palindrome (13121555512131).

The spelling of 13001223302100 in words is "thirteen trillion, one billion, two hundred twenty-three million, three hundred two thousand, one hundred".