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130012310323241 is a prime number
BaseRepresentation
bin11101100011111011011001…
…100100101100000000101001
3122001100001111110001111120122
4131203323121210230000221
5114020110202420320431
61140302455242533025
736246036151551623
oct3543733144540051
9561301443044518
10130012310323241
1138475a02844295
12126b930b807175
135771153ac0518
1424168b50b9c13
151006dba1b6a7b
hex763ed992c029

130012310323241 has 2 divisors, whose sum is σ = 130012310323242. Its totient is φ = 130012310323240.

The previous prime is 130012310323153. The next prime is 130012310323243. The reversal of 130012310323241 is 142323013210031.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 81248680578025 + 48763629745216 = 9013805^2 + 6983096^2 .

It is an emirp because it is prime and its reverse (142323013210031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 130012310323241 - 222 = 130012306128937 is a prime.

Together with 130012310323243, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 130012310323241.

It is not a weakly prime, because it can be changed into another prime (130012310323243) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65006155161620 + 65006155161621.

It is an arithmetic number, because the mean of its divisors is an integer number (65006155161621).

Almost surely, 2130012310323241 is an apocalyptic number.

It is an amenable number.

130012310323241 is a deficient number, since it is larger than the sum of its proper divisors (1).

130012310323241 is an equidigital number, since it uses as much as digits as its factorization.

130012310323241 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2592, while the sum is 26.

Adding to 130012310323241 its reverse (142323013210031), we get a palindrome (272335323533272).

The spelling of 130012310323241 in words is "one hundred thirty trillion, twelve billion, three hundred ten million, three hundred twenty-three thousand, two hundred forty-one".