1300124121320 has 128 divisors (see below), whose sum is σ = 2977648128000. Its totient is φ = 510819590400.

The previous prime is 1300124121319. The next prime is 1300124121341. The reversal of 1300124121320 is 231214210031.

It is a Harshad number since it is a multiple of its sum of digits (20).

It is a junction number, because it is equal to n+sod(n) for n = 1300124121292 and 1300124121301.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 833946701 + ... + 833948259.

It is an arithmetic number, because the mean of its divisors is an integer number (23262876000).

Almost surely, 2^{1300124121320} is an apocalyptic number.

1300124121320 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1300124121320, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1488824064000).

1300124121320 is an abundant number, since it is smaller than the sum of its proper divisors (1677524006680).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1300124121320 is a wasteful number, since it uses less digits than its factorization.

1300124121320 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2943 (or 2939 counting only the distinct ones).

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 1300124121320 its reverse (231214210031), we get a palindrome (1531338331351).

The spelling of 1300124121320 in words is "one trillion, three hundred billion, one hundred twenty-four million, one hundred twenty-one thousand, three hundred twenty".