Base | Representation |
---|---|
bin | 11000001101111000… |
… | …00001100101010111 |
3 | 1020120002020111011011 |
4 | 30012330001211113 |
5 | 203111313102221 |
6 | 5550034553051 |
7 | 640120141426 |
oct | 140674014527 |
9 | 36502214134 |
10 | 13001300311 |
11 | 557199339a |
12 | 262a138787 |
13 | 12c273880c |
14 | 8b49c72bd |
15 | 51160c1e1 |
hex | 306f01957 |
13001300311 has 2 divisors, whose sum is σ = 13001300312. Its totient is φ = 13001300310.
The previous prime is 13001300281. The next prime is 13001300327. The reversal of 13001300311 is 11300310031.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13001300311 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13001300291 and 13001300300.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13001300111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6500650155 + 6500650156.
It is an arithmetic number, because the mean of its divisors is an integer number (6500650156).
Almost surely, 213001300311 is an apocalyptic number.
13001300311 is a deficient number, since it is larger than the sum of its proper divisors (1).
13001300311 is an equidigital number, since it uses as much as digits as its factorization.
13001300311 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 27, while the sum is 13.
Adding to 13001300311 its reverse (11300310031), we get a palindrome (24301610342).
The spelling of 13001300311 in words is "thirteen billion, one million, three hundred thousand, three hundred eleven".
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