Base | Representation |
---|---|
bin | 1011110100110001101001… |
… | …1101101111111100000100 |
3 | 1201000220122122111222201121 |
4 | 2331030122131233330010 |
5 | 3201003140330324030 |
6 | 43352415214403324 |
7 | 2511212403456013 |
oct | 275143235577404 |
9 | 51026578458647 |
10 | 13001310011140 |
11 | 4162908615530 |
12 | 155b8a8500544 |
13 | 7340311ba039 |
14 | 32d3a3dd0a7a |
15 | 1782d96a347a |
hex | bd31a76ff04 |
13001310011140 has 96 divisors (see below), whose sum is σ = 29813431173120. Its totient is φ = 4723209955200.
The previous prime is 13001310011113. The next prime is 13001310011177. The reversal of 13001310011140 is 4111001310031.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1279777381 + ... + 1279787539.
It is an arithmetic number, because the mean of its divisors is an integer number (310556574720).
Almost surely, 213001310011140 is an apocalyptic number.
13001310011140 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13001310011140 is an abundant number, since it is smaller than the sum of its proper divisors (16812121161980).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13001310011140 is a wasteful number, since it uses less digits than its factorization.
13001310011140 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 15193 (or 15191 counting only the distinct ones).
The product of its (nonzero) digits is 36, while the sum is 16.
Adding to 13001310011140 its reverse (4111001310031), we get a palindrome (17112311321171).
The spelling of 13001310011140 in words is "thirteen trillion, one billion, three hundred ten million, eleven thousand, one hundred forty".
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