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13001312110000 = 24546437612657
BaseRepresentation
bin1011110100110001101010…
…0101110000010110110000
31201000220122210110121211011
42331030122211300112300
53201003141400010000
643352415331400304
72511212430350104
oct275143245602660
951026583417734
1013001312110000
114162909819425
12155b8a9153094
13734031773476
1432d3a43b9904
151782d996a2ba
hexbd31a9705b0

13001312110000 has 200 divisors, whose sum is σ = 31579739486064. Its totient is φ = 5183662080000.

The previous prime is 13001312109997. The next prime is 13001312110063. The reversal of 13001312110000 is 1121310031.

It is a tau number, because it is divible by the number of its divisors (200).

It is an unprimeable number.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 4893228672 + ... + 4893231328.

Almost surely, 213001312110000 is an apocalyptic number.

13001312110000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13001312110000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (15789869743032).

13001312110000 is an abundant number, since it is smaller than the sum of its proper divisors (18578427376064).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13001312110000 is an equidigital number, since it uses as much as digits as its factorization.

13001312110000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4089 (or 4068 counting only the distinct ones).

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 13001312110000 its reverse (1121310031), we get a palindrome (13002433420031).

The spelling of 13001312110000 in words is "thirteen trillion, one billion, three hundred twelve million, one hundred ten thousand".