Base | Representation |
---|---|
bin | 11101100011111100111111… |
… | …100000100011011001001000 |
3 | 122001100012220122002021011222 |
4 | 131203330333200203121020 |
5 | 114020122203222443100 |
6 | 1140303341054141212 |
7 | 36246126426133610 |
oct | 3543747740433110 |
9 | 561305818067158 |
10 | 130014020515400 |
11 | 38476700138a3a |
12 | 126b97084b1808 |
13 | 57713671c7c48 |
14 | 24169d8295a40 |
15 | 1006e6a3d0485 |
hex | 763f3f823648 |
130014020515400 has 96 divisors (see below), whose sum is σ = 345468268943040. Its totient is φ = 44575920380160.
The previous prime is 130014020515279. The next prime is 130014020515441. The reversal of 130014020515400 is 4515020410031.
It is a self number, because there is not a number n which added to its sum of digits gives 130014020515400.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 288282479 + ... + 288733121.
It is an arithmetic number, because the mean of its divisors is an integer number (3598627801490).
Almost surely, 2130014020515400 is an apocalyptic number.
130014020515400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
130014020515400 is an abundant number, since it is smaller than the sum of its proper divisors (215454248427640).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130014020515400 is a wasteful number, since it uses less digits than its factorization.
130014020515400 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 656743 (or 656734 counting only the distinct ones).
The product of its (nonzero) digits is 2400, while the sum is 26.
Adding to 130014020515400 its reverse (4515020410031), we get a palindrome (134529040925431).
The spelling of 130014020515400 in words is "one hundred thirty trillion, fourteen billion, twenty million, five hundred fifteen thousand, four hundred".
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