Base | Representation |
---|---|
bin | 11000001101111110… |
… | …00100111001010110 |
3 | 1020120010202010112202 |
4 | 30012333010321112 |
5 | 203112014202220 |
6 | 5550104044502 |
7 | 640130012663 |
oct | 140677047126 |
9 | 36503663482 |
10 | 13002100310 |
11 | 557238a451 |
12 | 262a463732 |
13 | 12c29589a4 |
14 | 8b4b54a6a |
15 | 511719275 |
hex | 306fc4e56 |
13002100310 has 64 divisors (see below), whose sum is σ = 25067568960. Its totient is φ = 4838522880.
The previous prime is 13002100297. The next prime is 13002100343. The reversal of 13002100310 is 1300120031.
It is a super-2 number, since 2×130021003102 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13002100291 and 13002100300.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 6071840 + ... + 6073980.
It is an arithmetic number, because the mean of its divisors is an integer number (391680765).
Almost surely, 213002100310 is an apocalyptic number.
13002100310 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13002100310 is a deficient number, since it is larger than the sum of its proper divisors (12065468650).
13002100310 is a wasteful number, since it uses less digits than its factorization.
13002100310 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2561.
The product of its (nonzero) digits is 18, while the sum is 11.
Adding to 13002100310 its reverse (1300120031), we get a palindrome (14302220341).
The spelling of 13002100310 in words is "thirteen billion, two million, one hundred thousand, three hundred ten".
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