130021133331132 has 18 divisors (see below), whose sum is σ = 328664531476008. Its totient is φ = 43340377777032.

The previous prime is 130021133331119. The next prime is 130021133331143. The reversal of 130021133331132 is 231133331120031.

130021133331132 is a `hidden beast` number, since 1 + 3 + 0 + 0 + 2 + 11 + 333 + 311 + 3 + 2 = 666.

It is a tau number, because it is divible by the number of its divisors (18).

It is a super-2 number, since 2×130021133331132² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 130021133331096 and 130021133331105.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 1805849074008 + ... + 1805849074079.

It is an arithmetic number, because the mean of its divisors is an integer number (18259140637556).

Almost surely, 2^{130021133331132} is an apocalyptic number.

130021133331132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

130021133331132 is an abundant number, since it is smaller than the sum of its proper divisors (198643398144876).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130021133331132 is a wasteful number, since it uses less digits than its factorization.

130021133331132 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3611698148097 (or 3611698148092 counting only the distinct ones).

The product of its (nonzero) digits is 2916, while the sum is 27.

Adding to 130021133331132 its reverse (231133331120031), we get a palindrome (361154464451163).

The spelling of 130021133331132 in words is "one hundred thirty trillion, twenty-one billion, one hundred thirty-three million, three hundred thirty-one thousand, one hundred thirty-two".